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I know that this is a very fundamental (and maybe vague) question.
But I'm not sure what period I should use. I read somewhere that a constant signal doesn't have a fundamental period but is periodic. So looking at the formulas for calculating energy and power would that mean that a constant signal is an energy signal?
Thank you for your replies, please let me know if you need more clarification. ( I am new to this topic)
Suppose x(t) = K is a constant signal.
The energy which will be dissipated on a unit 1 ohm resistor by x(t) can be computed as: $$ \begin{align} E&=\int_{-\infty }^{\infty }\left | x(t) \right |^{2} dt\\ &=K^2\int_{-\infty }^{\infty }dt \\ &= \infty \end{align} $$ The power which will be dissipated on a unit 1 ohm resistor by x(t) can be computed as: $$ \begin{align} P&=\lim _{T->\infty}\frac{1}{2T}\int_{-\infty }^{\infty }\left | x(t) \right |^{2} dt\\ &=K^2\lim _{T->\infty}\frac{1}{2T}\int_{-T }^{T}dt\\ &=K^2\lim _{T->\infty}\frac{2T}{2T}\\ &=K^2 \end{align} $$
Therefore x(t) has finite power but infinite energy. Which implies a constant signal is a power signal.
Refer: Energy and Power Signals
So looking at the formulas for calculating energy and power would that mean that a constant signal is an energy signal?
