In one of my laboratory assignments, I am to study how to work with square signals in RC circuits (low pass filter). Please keep in mind this is an introductory Electronics course. Basically, I am thinking of using a 1k\$\Omega\$ resistot and a 6.8 nF capacitor. My square signal has an amplitude of 5 voltage peak-to-peak. Then, I am asked to start by setting the frequency of the generator such the output voltage as measured accros the capacitor is 63% of the input voltage.
This seems fairly easy: I need the Vpp of the output signal to be \$0.63*5V = 3.15 V\$, so then I just move the frequency button on the generator until I get this value on the screen, right? And the time constant would be half the period since a capacitor charges to 63% in one time constant, right? Another part asks whether we can measure the peak to peak voltage of the output. To me, this is confusing since the capacitor has not enough time to completely charge and discharge, so wouldn’t the peak to peak voltage change continuously? It would just make sense to define these limits for one period.
I appreciate any help I can get. I know these are basic questions but I have to be at the lab tomorrow and I want to be prepared to work as well as possible. Thank you.