Why is AC current inversely proportional to voltage?
I think that current should be proportional to voltage, because according to \$V=IR\$, when \$R\$ is fixed, the bigger \$I\$ is, the bigger \$V\$ should be. But according to this simulation, the relationship between \$I\$ and \$V\$ is negative. Is the software the problem? I use Virtuoso Cadence to simulate the circuit.
I have another question. The direction of the arrow should be the direction of the current. Why is the first half wave negative?
Is the meter "flipped around" in 1 (below)? Or, should I modify something in 2? I had tried simulating 1, but it didn’t change the relation between the voltage and current.