A 0.56 kW induction motor is operating from a 240 V 50 Hz supply. Its synchronous speed is 1,050 rpm and its rated speed is 880 rpm. It produces no torque at 1,050 rpm and its rated torque is 6.08 Nm.
Assume a linear τ - ω relationship near synchronous speed, and hence calculate the speed (in rpm) corresponding to 2/3s of the rated torque.
I have used the equation so far that: 0.56 kW/6.08*2/3 = Speed
That answer is wrong, so is anyone able to help me with this one?