I've always been intrigued by common-mode noise, as it seems to be such a pertinent issue when it comes to op-amps, chokes, etc. used as solutions to remove it.

I understand from a digital signal point of view (as explained very well here) why it is a bad thing, as on a differential pair it means the differential voltage (V+ - V-) taken at the receiver will bounce and fluctuate around some value (the common-mode voltage), when you would in reality want this to be stable.

What I still haven't quite understood is why it is a bad thing on power lines (mainly low voltage ones, not really talking about mains voltage here but I suppose it's the same deal). Like such, consider a power supply (maybe even isolated) that has an output of 24V. It is fairly common from the designs I have seen to use a choke on the output:

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What exactly would this achieve? I could be wrong but no matter what the common-mode noise is, the device being powered won't care as the only voltage that matters is the differential voltage relative between the two rails. I.e. at an instance of time, say the common-mode noise is rapidly bouncing between -10V and +3.5V. The rails (Vcc, GND) will be bouncing between (14V, -10V) and (27.5V, 3.5V), which still leaves the differential at (14 - -10) (27.5-3.5) 24V in either extreme (duh).

So, why is the choke helpful at all?

They have a whole category on Digi-Key ("Common Mode Chokes > Power Line"), so surely there is some reason they are used.

  • \$\begingroup\$ Well, you could look at it like this: If I inject the noise equal to opposite on the other power rail, it transforms the noise from common to differential so it will be nulled at the circuits. \$\endgroup\$
    – drtechno
    Commented May 1, 2018 at 11:51

2 Answers 2


Why is common-mode noise on a power line bad?

Say you have 100 mV p-p at 100 kHz common mode voltage on the output of a power supply that feeds a target circuit. If that circuit was totally isolated from earth in all its nodes then there would be no problem.

However, just think about what a CM voltage is - it's the same voltage on both lines but with respect to earth. The device connected to the power supply might be quite sensitive and even though it may not be intentionally connected to earth, different nodes of that circuit will have capacitance to earth and if all nodes have exactly the same capacitance to earth then again, there will be no problem.

What are the chances that the target circuit has all its nodes isolated from earth and all its nodes have the same capacitive impedance to earth?

  • \$\begingroup\$ Lovely answer. Thanks. Still new to isolated power supplies, and always forget about incidental capacitive coupling to earth in all circuits (especially if its high-frequency CMV, as the capacitive impedance will be small etc.). \$\endgroup\$
    – DSWG
    Commented May 1, 2018 at 23:03

It doesn't necessarily improve the operation of the device itself at all.

It does reduce the emission of RF by the device, conducted down the power line. So it does improve the operation of other, RF sensitive devices around it.

If it was a sensitive device, then it might also improve its robustness to interference received on the power line.


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