# AC current probe readings connected to an oscilloscope

I have a Fluke clamp on reading a 11 amps on for an AC load. I bought two different AC-DC current probes for the scope. The DC readings are great and match dc loads. When reading the AC load for the 11amps on the scope, I get 160mv peak or 320 peak to peak. The probe claims 40amp scale use 1mv=100ma. This gives me 16,000ma peak or 32,000ma peak to peak. How does this calculate to 11amps?

so if they measure Vpp then conversion is 1/(2√2) to $I_{RMS}= \frac{32A_{pp}}{(2*√2)}=11.3A$