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I'm going to try and explain my problem statement first and then explain my solution and then ask for suggestions. So, my problem statement is this: To determine changes in permittivity from a distance. Ie..non-contact measurement. To be more specific: I need to determine changes in biological permittivity (alpha and beta dispersions).

What I am doing is using the AD5933 evaluation board from Analog Devices to achieve this. I have calibrated the setup with the instructions and formula mentioned in the AN-1252 application note. My frequency sweep is between 10-100kHz. My impedance range is between 100-500kOhm. I have arrived at this frequency range by considering the parallel plate capacitor I have made to be filled with air as a dielectric. I know this is not the "perfect" parallel plate capacitor, but my setup is isolated from the environment ie. the area around the setup is absolutely cleared. So even if there are fringing effects (which there are obviously) there is nothing in or around the setup to disturb this. The voltage range I have chosen is range 1( 2Vpp as mentioned in the datasheet). I then amplify this voltage to 20V using an external amplifier that I have made. There is a phase change between the input and output of the amplifier however I think this will not affect the reading.

I have used the classical parallel plate formula to arrive at the expected impedance range. One thing to note is that I have used a spacing of d = 4.6mm rather than the actual spacing (16cm). The reason for this being that I have placed by capacitor plates across a Solartron impedance analyzer and used this as a reference, and a Solartron would NOT give me a correct value if I made the spacing to 16cm. So what I have done is first computed the expected impedance for this capacitance value (A = 8100 mm2, k = 1, d = 4.6mm). I then put the capacitor plates in the setup I have indicated below and arrived at a spacing of d = 16cm with an amplification of the excitation voltage to 20V.

I then measured the impedance across it, which was as expected. This gave me a permittivity of air~0.97.

My problem arises when I place other dielectrics. Rather, when I place liquid and biological materials.

I tested my setup by placing a wooden slab of 3 cm and got a permittivity of 2.5. Which is also expected, so far so good. I then placed acrylic of 3cm across the plates and got a permittivity of ~ 2 . This is also acceptable.

When I place water is when things go awry. I tried with water and cucumber. Since the water and cucumber only occupy a portion of the capacitance, I used the stacked dielectrics formula (parallel capacitance, water and air & cucumber and air) to calculate the capacitance of water and cucumber respectively.

I get the expected impedance value for the air+water and air+cucumber combo. However, when I try to find the capacitance of just the water or cucumber from this, I get a very different value as compared to my theoretical value. How I calculate is I take the observed capacitance C and then reverse calculate C3 using the stacked dielectric (both parallel and series) formula. Please keep in mind that I am using a scaling factor here ( 4.6mm to 16cm) since the AD5933 "thinks" that the spacing is 4.6mm. So basically I did 0.46/12 = 0.03833 as "1cm" of actual width.

So, my question finally, can someone shed some light on what I am doing wrong? A lot of this is based on my assumption that things are ideal, so indeed I expect a deviation from my theoretical permittivity, but right now I'm getting a completely wrong value. Should I instead of scaling, calibrate my system for d=16cm? I am afterall using 20V excitation instead of 2V as the system original config is, so maybe that would help? Should I also maybe use a circuit to remove the phase change after the external amplifier?

Also, I am calculating the capacitance from the IMPEDANCE value of the AD5933. I am NOT using the imaginary value output since the imaginary value given out is actually the imaginary value of the DFT. And so should I perhaps calculate the imaginary value from the impedance? That would involve finding out the accurate phase angle. Is the phase output of my complex impedance the correct phase then (since I did calibrate as the datasheet mentions) ?

I have used de-ionized water.

I would really appreciate some light on this matter. I've tried to provide full and complete info what I'm doing. Anything else and I shall also try to answer.

My readings 1 Setup with cucumber as C4 Wood Water Setup

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  • \$\begingroup\$ Was your sample of water de-ionized (i.e. an insulator)? \$\endgroup\$ – Spehro Pefhany May 7 '18 at 19:10
  • \$\begingroup\$ First, you tell us the measured and predicted values differ, but you tell us neither the measured nor predicted values, nor do you show your actual calculations. Secondly you don't mention that both your "water" (unless de-ionised) and your cucumber are conductive or how you measured their conductivity or factored that into your analysis. Consider trying other known conductors (maybe a 3cm lump of graphite?) to correlate with your liquid results. \$\endgroup\$ – Brian Drummond May 7 '18 at 19:10
  • \$\begingroup\$ I'll update the question with all this info. :) \$\endgroup\$ – Richeek D May 7 '18 at 19:14
  • \$\begingroup\$ If your actual spacing is 160mm your impedance is actually of the order of 3M-30M if I did the math right, so even a bit of conductivity is quite significant. \$\endgroup\$ – Spehro Pefhany May 7 '18 at 19:16
  • \$\begingroup\$ @SpehroPefhany yeah it is but as I said, I've "scaled" my readings to 4.6mm since the system "thinks" that its 4.6mm. I've only compensated for this with the gain of the amplifier. So with no gain and spacing of 4.6mm = gain with spacing of 16 cm \$\endgroup\$ – Richeek D May 7 '18 at 19:48
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You have several issues to correct:

You should be driving with a current source thus impedance is proportional to voltage.
Your amp needs 2 decades more BW to be flat phase response to measure complex impedance or a PLL tuned to say 2 frequencies 100k and 1 MHz.
The wires need to be balanced and controlled impedance or at least a low L/C ratio so self resonance is a non issue.

Your dielectric cucumber needs to fill the plate gap so use a sample slice and narrow gap so that there is no air gap which introduces error with C in series .

The area/gap ratio needs to be maximized unless there are untold reasons and the gap needs to be filled with the sample.

Two PLLs in Quadrant sure can extract the real and imaginary values or you can measure the apparent impedance which is the hypotenuse and the tan. delta the angle or phase difference between voltage and current. With a PLL you can have extremely small band with’s with the low pass filter to the Visio and thus have extremely high immunity to interference and does have a very high signal to noise ratio and thus have very accurate and consistent readings. For a thin bag of water for example between the plates you should get a dielectric constant or permittivity of 80.

The original methods of doing this involved matching the impedance to the sample under test which is how Wheatstone and others measured impedance. For small values of capacitance this can be done with voltage controlled resistors and voltage controlled diode capacitance but I suggest that you choose any method that you know how to use. My experience doing this was some 45 years ago with 10 ppm resolution for R,X. The real and imaginary values were automatically calibrated with two references to get the correct gain and phase error nulled where we used sine-cosine phase lock loops At 100k and 200 kHz for 1 mm thickness that worked out best in our case.

Your gap may be variable for different samples as long as you calibrate and get consistent air results.

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  • \$\begingroup\$ Okay thanks. As for the gap, there has to be a gap between the cucumber and the plates. So the air+cucumber is a part of my calculation. Its not an error. So if I replace the amp with a PLL, that would give me better values? \$\endgroup\$ – Richeek D May 8 '18 at 8:50
  • \$\begingroup\$ Yes a PLL in quadrature to detect magnitude in phase of the voltage will give far better results, however the air will introduce more errors Then if you were to immerse the cucumber in a dielectric of water which is closer to the dielectric of the sample. The ratio volume of the sample to the volume between the plates will determine the errors you can expect. Examine the The bridge mouth at work and unknown impedance is compared to a known impedance that is matched. In this case you were comparing the cucumber to water which is closer than air in impedance. Does that make sense? \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 May 8 '18 at 16:15
  • \$\begingroup\$ For an even better bridge method use two sets of parallel plates filled with water and then immerse the sample in one. Now you can sweep frequencies of cookout and look for the optimum frequency to give both real and reactive permittivity of your sample with much higher accuracy \$\endgroup\$ – Tony Stewart Sunnyskyguy EE75 May 8 '18 at 16:19
  • \$\begingroup\$ Yeah that does make sense. Thank you. However, for this project, I have to keep air + material. The idea is to observe permittivity from a distance. The next step in this is to put this up on a wall and the "sensor" would then detect permittivty, does that make sense? Like, one capacitor plate would be on one wall and the receive end would be on the opposite wall. So if material is brought in between, it should be able to characterize it by the permittivity, so I can't replace the air with anything else. \$\endgroup\$ – Richeek D May 9 '18 at 7:50
  • \$\begingroup\$ What I can do is perhaps conduct some tests with the ratio of material/air to determine how the error is. That would help enormously. Also, I have to use this board (AD5933), so I guess I cant go the PLL route either. \$\endgroup\$ – Richeek D May 9 '18 at 7:51

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