# Isolation between measuring voltage from low current circuit?

simulate this circuit – Schematic created using CircuitLab

I have a low current current circuit and I would like to be able to measure the voltage on one point of the circuit but have electrical isolation between the low current circuit and the circuit for measuring the voltage. Needs to be impossible for higher voltage to make it to the low current circuit. Any ideas?

• How "isolated" do you want this to be? Is it life-critical (someone dies if the voltage goes across), equipment-critical (your laptop or some other expensive stuff breaks if the voltage goes across), or "it's kind of annoying" critical (you don't want high voltage messing up your measurement, and failure doesn't result in any sort of monetary loss) that the voltage measuring circuit doesn't touch the low current circuit? – hatsunearu May 8 '18 at 13:26
• Or rather, rephrasing: what is the worst that could happen if the higher voltage from the Arduino makes its way to the circuit under test? Does someone die? Does your invaluable widget break? If neither, how much risk can you tolerate? I ask because if it is non-negotiable that there be perfect/guaranteed galvanic isolation, you're looking at much higher costs, and may be even impossible. – hatsunearu May 8 '18 at 13:29
• Potentially life critical but not really (erring on the paranoid safety side) – anna May 8 '18 at 13:30
• You're gonna need a power supply on the other side (i.e. the side that is galvanically connected to the DUT) one way or another; is this acceptable? (perhaps using a coin cell or 9V battery) – hatsunearu May 8 '18 at 13:31
• If your worry is too high current injected by the voltage place three 5 megaohm resistors in series to the measurement circuit. That way you are pretty safe that you will only ever inject maximum fault voltage divided by 5 megaohm. – Arsenal May 8 '18 at 13:37