# In series RLC circuit, does increasing capacitance value really make the circuit more inductive circuit?

This seems very counter intuitive to me. How can increasing capacitance value make the circuit more inductive ? The math tells me so :

If $C$ increases then $X_c = \dfrac{1}{\omega C}$ decreases, so the circuit becomes more inductive.

But I've heard that factories that use heavy motors have a large $X_L$. For this reason they need to increase $X_C$ so that $X_L = X_C$. To increase $X_C$ they seem to "add" capacitors. But adding capacitors actually decreases $X_C$ right ? $X_C \propto \dfrac{1}{C}$. How does this work ?

Definitions :
$X_C\gt X_L$ : more capacitive circuit

$X_L\gt X_C$ : more inductive circuit

• Depends how you add them! Think about how capacitance gets bigger. – StainlessSteelRat May 14 '18 at 14:30
• Then your circuit is inductive. Power is going back and forth between source and inductor. Add any capacitor and now some of that power goes between capacitor and inductor. – StainlessSteelRat May 14 '18 at 14:34
• With heavy motors, you aren't increasing series capacitance. – user_1818839 May 14 '18 at 14:35
• Always in parallel for power factor correction – StainlessSteelRat May 14 '18 at 14:38
• For pawer factor correction? No they don't, as I said - the capacitors are connected in parallel. – user_1818839 May 14 '18 at 14:38