A coil of 100 turns and a diameter of 3.18cm is mounted on an axle through a diameter and is place in a uniform magnetic field, where the flux density is 0.01T, in such a manner that the axle is normal to the field direction. Calculate. (i) The maximum flux through the coil and the position at which it occurs. The maximum flux through the coil and the position at which it occurs.
(ii)The minimum flux through the coil and the position at which it occurs.
(iii) The flux through the coil when it's plane is inclined at 60 degrees to the flux direction.
Data N= 100t d= 3.18cm = 0.0318cm B= 0.01T Angle(teta) =60 degrees
SLN. (iii) Flux =BAsin get a But A= pi*r square But r=1/2*d = d/2
A=pi(d/2)square =3.142*0.00101142/4 =0.0031773161/4 =0.00079m or 79mm It implies that Flux = BA sin-teta = 0.01*0.00079*0.866 = 0.0000079*0.866 = 0.0000068416wb or 0.00684mwb
Now my problem is the formular for finding (i) and (ii) pls any help