-3
\$\begingroup\$

Can anyone help me find some causes as to why a resistor may become non-ohmic?

Thanks in advance.

\$\endgroup\$
3
  • \$\begingroup\$ If you make a resistor using thin wire, say steel, you will find that the resistance increases with wire temperature. So that is one example. There are special resistors designed to have a temperature dependence. Some have a negative temperature coefficient (NTC) and some have positive (PTC). They can be used for temperature sensing or other special uses (for example PTC's can act somewhat like a fuse, and NTC's can act as inrush limiters). \$\endgroup\$
    – user57037
    Commented May 20, 2018 at 6:30
  • 3
    \$\begingroup\$ You need to define what you mean by non-ohmic. Has the component become open circuit and in effect looking like nearly infinite resistance? Has the component become a short circuit? Or is it still acting somewhat like a resistor but not in a linear relationship between current through and voltage drop across? \$\endgroup\$ Commented May 20, 2018 at 6:35
  • 1
    \$\begingroup\$ now that i think about it, this looks like a school question .... is it a school work? \$\endgroup\$
    – jsotola
    Commented May 20, 2018 at 6:39

1 Answer 1

1
\$\begingroup\$

An ideal resistor follows Ohm's law by definition.
Materials which do not follow Ohm's law are not called resistors. That being said, it is possible that a material that follows the law under standard conditions fails to do so under a wide range of conditions.
Two reasons that come to mind are,

  • The Skin Effect: Which is applicable to High frequency AC circuits
  • Thermal Dependence of resistivity, because of which the nature of the conductor changes with temprature.
\$\endgroup\$
1
  • 3
    \$\begingroup\$ Be careful that you are not doing homework for the OP (original poster). If we suspect that it is a homework we usually prompt the OP with some clues to let him/her think it through themselves. They're supposed to be studying the subject so they should already have enough background information. \$\endgroup\$
    – Transistor
    Commented May 20, 2018 at 9:17

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.