The circuit above is a PNP Voltage Divider Bias BJT. From the book, to get the emitter current, the circuit was transformed first into a Thevenin equivalent circuit then applied KVL from base to emitter:
Vth + (Ib)(Rth) - Vbe + (Ie)(Re) = 0
Where Vth = Vcc (R2 / R1 + R2) and Rth = (R1)(R2) / (R1 + R2)
Finally, Ie = (-Vth + Vbe) / [Re + (Rth / Beta)]
1.) From the KVL done from base to emmiter, shouldn't it be -Vth as this is PNP type and the polarities are reverse. Also, why is Vbe is "-" when it should have been reversed too when in PNP? Also, the source Vcc is negative.
2.) If I want to get Vce, applying KVL from Vcc to emitter ground, is: -Vcc + IcRc + Vce = 0 right? Vcc starts from negative, so the polarity of the Rc is negative to positive which is the same for Vce.
3.) When getting Vce, looping at either from emitter ground or from source, why are we ignoring IeRe in the loop when getting Vce?
Note: The book didn't show the Thevenin equivalent for the PNP VDB, it was just stated that it is the opposite of the previewed NPN VDB.