I am doing the nodal analysis of this circuit:
I have successfully wrote the current equations for node A, using nodal analysis, that I found it to be:
i3 = i5 + i7 or (Vc-Va)/R3 = (Va-Vb)/R5 + i7
where i7 is the current source value of 1A.
That will give me
-9Va + 3Vb + 5Vc = 400
So far, so good...
Now analyzing node C I have a doubt.
The currents for node C would be:
i1 = i3 + i6
i1 = (V1-Vc)/R1 = (12-Vc)/20 i3 = (Vc-Va)/R3 = (Vc-Va)/80
but what about i6?
I know that i2 = i6 + i7 resulting on i6 = i2-i7 or substituting the value for i7,
i6 = i2 - 1
The problem here is, how can I declare i2 in terms of voltages and resistors? If the current source was not there I would say i2 = Vc/R2 but with the current source there I don't now.
Any help is welcome. Thanks.