# Gate Drive Resistor size and/or Gate Driver IC

I am working on a design for a 16 channel LED driver design. at the moment the basic design is based on three main components:

the Circuit needs to initially drive a 110V led Light with 250mA LED strings but wants to be adjustable to driver sets of other LEDs e.g Ledengin LZ7

simulate this circuit – Schematic created using CircuitLab

without further components i think this design should work in principle with M1 getting a RDS(on) of ~30 mOhm (other similar mosfets had larger RDS(on)). the RDS(on) can be reduced further if i can supply higher voltage (14.1 mOhm at 6V and 12.6 at 10V)

(this combination of R2, M1 Q1 R2 and D1..n are repeated for each channel though R1 will be varied dependent on different D1..n on each channel)

the PCA9685 can supply limited current of 10mA per channel and if im reading it right 25mA total and can operate PWM at upto 1526 Hz

some simulation at 1526Hz PWM (assuming i did it right) shows if i have R2 with 10K resistor i get inrush current of 500uA which should be no issue

if i reduce r2 to 1k i get 5mA which is likely too large to operate more than 4 channels at once

and 100 gets 50mA which too large for a single channel and the PCA9685.

How do i determine the best value for R2?

Would the inefficiency of resulting from a large R2 make it worth putting in a gate driver e.g a MAX620EWN+ (would need 4) or a cheaper alternative?

or is there another, cost effective?, way to make this more efficient?

simulation model and output( the New macro are a PLW7070GA spice model)

• If you only need 250mA of current, then you are really over spec'ing your RDSon. Also, your FET is only rated for 100V, not 110V+margin. – W5VO Jun 12 '18 at 21:50
• correct me if im wrong but isn't the voltage across the MOSFET (Source - LED Forward Voltage) – fireblade Jun 13 '18 at 13:33
• so for a 110V supply as long as the voltage drop across the LED array is >10V+margin this wouldn't be an issue ? and would ideally choose a voltage source to minimize the voltage across the mosfet to me more efficient – fireblade Jun 13 '18 at 13:39
• When the MOSFET is off, the current through the MOSFET and LED chain will be close to 0A. That makes the voltage drop across the LED almost 0V, and the rest is across the MOSFET. Picking a bigger MOSFET (lower RDSon) means you have larger gate capacitance, slower turn on/off, and more power dissipation from switching. Unless you're using a switch-mode driver for controlling LED current, "efficiency" is irrelevant - you will burn the difference between the forward voltage of the LED and your power supply somewhere. – W5VO Jun 13 '18 at 17:29
• that's interesting as the simulation of the circuit in TINA-TI doesn't show that simulating a set of PLW7070GA leds and CSD19534KCS, i only get a ~0-30V swing across the mosfet is there something wrong with the simulation? (ive added simulation info to post) – fireblade Jun 13 '18 at 18:42

## 1 Answer

R1 is going to be more reliable in setting the LED current. Q1 will start stealing volts from the base of the FET when Vbe (=Vr1) is 0.65V. As such, the above will attempt to adjust the LED current to 650mA. R2 is serving to limit this, but the semiconductor parameters keep R2 from easily controlling the current...across devices and conditions, the current limited by R2 will change dramatically.

I'd say stick with R2=100 and R1=0.65V/Iled (where Iled is the current you want to push through the LEDs).

• I know that R1 is used to limit the current through the LED, however that is not what i am asking. Im asking about the value of R2 and its effect on the current through the PCA9685 also already stated that setting r2 to 100 would, as i understand it, likely overload the PCA9685, if you believe this is wrong can you explain why – fireblade Jun 12 '18 at 21:33
• The 100 would stress it by about 150% from spec. This is probably fine for a hobby project but unacceptable for volume production. How much current do you need? You could set R1 as needed, and then just decrease R2 until R1 is in control. – Cristobol Polychronopolis Jun 13 '18 at 12:11
• The reason R2 has such an effect is that with a 1K resistor, you need only 15uA of base current on the 2222 to draw the gate voltage nearly down to the threshold. There's multiple places that could be coming from; without being there, I can't really speculate, but check the board for contaminants and try breaking some paths if you want to chase it down. – Cristobol Polychronopolis Jun 13 '18 at 12:27
• currently there is no actual board an im working from simulations. I am trying to workout how to make the Mosfet work most efficiently while still protecting the the PCA9685. Idealy this would be capable of operating all 16 channels simultaneously which due to single pwm clock would mean a total of upto 16x the inrush current of any individual channel. – fireblade Jun 13 '18 at 14:08