# Why have resistors in a circuit down-stepping 230VAC

I'm trying to build a unit which will convert mains voltage (230vac) to approx 80vac. I have a similar product which I know works for my propose - but it works in a way I don't quite understand. There is a resistor before the output/load and another one in parallel to it.

Here is a diagram of how it looks, with the switch and fuse removed. I've used a bulb to represent output/load. The transformer has a primary coil of 220V and two secondary coils of 24v.

Why has this been done? What advantage does it have over not having the resistors?

EDIT1: The two secondary coils are connected, presumably to make one large coil.

EDIT2: The circuit will be used to power an A4 sample of Smart Glass, which will need around 2W (defiantly no more than 5W). The circuit does have a switch, which I was surprised to find was placed in the 80V circuit. (ie after the transformer)

• What is the real load? (Made up questions get made up suitable answers alas) What is the output Wattage? 2 x 24VAC <> 80 VAC. Something is wrong. Presumably 230 VAC in and one primary winding only. With 820 ohms as shown Pmax out at 48 VAC RMS is about 0.7 Watt. Is that what you'd expect? And Vout will be 24 VAC with the other half dropped across the 820 R resistor. Aug 14, 2012 at 15:04
• I've added the what the load is into the question. Aug 15, 2012 at 11:54