0
\$\begingroup\$

I am designing a circuit to excite a piezo-electric crystal with 1MHz bipolar square wave at 30V (Vp-p=30V, Vb-p=15V) consisting of 10 pulses, 50% duty cycle.

The idea is to use a pulse transformer whose inputs shall be driven with +15V from either directions to achieve bipolar excitation. First, IN_A will be driven with +15V while IN_B is at ground and vice versa.

1) The voltage * time product in this case should be 15V * (1/1MHz) = 15V-us. Is this correct?

2) Or should it be 30V * (1/1MHz) = 30V-us since the excitation is bipolar?

3) Finally, since the excitation consists of 10 pulses and not just a single pulse, should the calculation of V * t value take that into account as well?

enter image description here

\$\endgroup\$
  • \$\begingroup\$ How do you reset the core? \$\endgroup\$ – winny Jul 3 '18 at 7:49
  • 2
    \$\begingroup\$ @winny OP says the driving is done +15 on IN_A, with IN_B grounded, then IN_A grounded and IN_B with +15, which is zero average. \$\endgroup\$ – a concerned citizen Jul 3 '18 at 9:44
  • 2
    \$\begingroup\$ @aconcernedcitizen Sure, but without some servo feedback for adjusting the duty cycle or the individual rails, it will never fully cancel out each other. \$\endgroup\$ – winny Jul 3 '18 at 9:59
  • \$\begingroup\$ @winny That's also true, if OP doesn't keep his 50% duty-ratio true. \$\endgroup\$ – a concerned citizen Jul 3 '18 at 13:46
  • \$\begingroup\$ @aconceredcitizen That, or missmatch between the rails. In practice, both. \$\endgroup\$ – winny Jul 3 '18 at 13:58
2
\$\begingroup\$

The limitation on transformer volt.seconds is the core flux.

A 1MHz square wave spends 0.5us in one state, and 0.5us in the other.

During the first 0.5 us at 15 V, and assuming it starts from zero flux, the core will go to a flux representing 7.5 Vus. During the second phase, the flux will go back to zero. Subsequent repeats will cycle the core through the same flux swing. If operated like this, you therefore need a 7.5 Vus core specification.

If you can contrive to deliver 'half' a pulse first, so 0.25 us to swing the core to 3.75 Vus, then full pulses of 0.5 us to swing it between +/- 3.75 Vus, finally finishing with half a pulse to get it back to zero, you can use a 3.75 Vus transformer.

\$\endgroup\$
  • 3
    \$\begingroup\$ Microseconds, not microsiemens! \$\endgroup\$ – winny Jul 3 '18 at 7:51
  • 1
    \$\begingroup\$ @winny I'll take your word for it (but look it up later), 's' has always looked wrong to me. \$\endgroup\$ – Neil_UK Jul 3 '18 at 8:32

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.