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enter image description here http://www.cheemi-tech.com/product-current-transformers-CMPT107.html

Voltage between B & C is 119V which is equal to 1.19mA but input current between A & B is 14mA. Why is it so?

Edit: In the common perforated board, unused parts are blurred

Edit 2: Let me assemble the circuit in another board and shall post the details. 05june18

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  • \$\begingroup\$ It can't be so. Unless you measure some momentary values of AC. \$\endgroup\$ – Eugene Sh. Jul 5 '18 at 14:39
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    \$\begingroup\$ Check the battery on your meter. \$\endgroup\$ – Andy aka Jul 5 '18 at 14:47
  • \$\begingroup\$ @Andy: Fresh batteries are replaced, same result. \$\endgroup\$ – John Jul 5 '18 at 14:56
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    \$\begingroup\$ What is the scale of your current setting on your meter? If it's something like 1 A or 0.1 A you're just seeing the difficulties of converting low currents to voltages. \$\endgroup\$ – WhatRoughBeast Jul 5 '18 at 14:57
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    \$\begingroup\$ How do you measure the current?\ \$\endgroup\$ – Eugene Sh. Jul 5 '18 at 15:09
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This is a meter error. If you look at the data sheet you'll see that the accuracy for AC current is 1.5% + 3 counts. However, if you look at the bottom of the page, you'll see that this is only specified over the range of 1% to 100% of the span. The smallest range in AC current is 4 amps, so any current less than 40 mA has no accuracy spec at all, and you simply can't trust it. 1.19 mA is less than 3% of 40 mA.

Don't believe your meter when you are misusing it.

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The section of the Fluke 106 datasheet mentioned by the user WhatRoughBeast is added for anyone who is interested. Thanks for all those who involved to find a solution.

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