# How to replace a relay with a MOSFET? [duplicate]

I currently use the circuit below to power the OUT output when the signal is high (5V). I have a problem related to the size of the circuit, using a relay takes up a huge space. With this I would like to know if anyone has any idea of circuit with the same logic however using MOSFET or BJT. The current OUT consumes is 3A. Signal when it is high has 5V and when it is low it has 0V.

simulate this circuit – Schematic created using CircuitLab

• ...with the same logic however using MOSFET or transistor FYI a MOSFET is a transistor. That's what the "T" stands for. Jul 5 '18 at 16:42
• @DerStrom8 Edition made. Jul 5 '18 at 16:50
• electronics.stackexchange.com/q/42030/76537 something like this? Jul 5 '18 at 17:00
• Here is a schematic showing a load (LED) being turned on and off with a resistor. If you cannot find a BJT/MOSFET that will conduct 3A, you can use more than one and add their ratings together i.e. 2 BJT that will each conduct 2A can together conduct 4A if you connect their bases together. Indeed your schematic in this question is using a BJT to power the relay. There is your circuit. Jul 5 '18 at 17:14