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schematic

simulate this circuit – Schematic created using CircuitLab

EDIT: I have boiled the problem down to it's simplest component. I need to use the Emitter of a PNP (2N3906) to be the base of a NPN (2N2222) to light an LED.

I have a circuit I'm trying to get to work. Here is the relevant part.

The battery is actually an at 11.1v (DC power supply). I know in this image the PNP is kind of pointless, but it's necessary for the overall project. If this isn't enough info I'll draw up the whole circuit, but I think this is the relevant part.

So when I push the button I need an LED to go light up from receiving the hot end of 5v. I need the same button to send a ground signal to a sound trigger (represented here by a Red LED). The blue light poriton of this works great, but for some reason the NPN is ALWAYS completing the circuit to the Red LED. I'm hoping to have it only complete the circuit to the LED when the button is engaged.
What am I doing wrong? The NPN is a 2222 The PNP is a 3906

schematic

simulate this circuit

Figure 3. OP's circuit redrawn in conventional manner reading from left to right with current flow from top to bottom.

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    \$\begingroup\$ hot end of 5v - there is no 5V in the circuit. \$\endgroup\$ – Eugene Sh. Jul 13 '18 at 19:19
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    \$\begingroup\$ Please draw the circuit using the schematics editor button while editing question..If not draw nicely on a paper and attach the pic.. \$\endgroup\$ – User323693 Jul 13 '18 at 19:21
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    \$\begingroup\$ @joeyarkenstat02 Use the schematic editor button that exists when you are editing your question. If you designed the schematic, you should be perfectly able to use a new editor to replicate your design. You should NOT need to force fritzing to produce one for you. (Unless you have no clues at all about schematics and you copied this fritzing thing from somewhere else.) \$\endgroup\$ – jonk Jul 13 '18 at 19:26
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    \$\begingroup\$ Q2 CE reversed .... change 10K to 1K for both LEDs \$\endgroup\$ – Tony Stewart EE75 Jul 13 '18 at 19:52
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    \$\begingroup\$ @joey: I've redrawn your schematic (as Figure 3) so you can see more clearly. \$\endgroup\$ – Transistor Jul 13 '18 at 20:02
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Maybe something like this is what you have mind, but from your description you could just use one switch and two resistors and no transistors.

schematic

simulate this circuit – Schematic created using CircuitLab

Even if you put the PNP in there for some reason, R2+D1 and R3+D2 could be put in parallel and lose the NPN.

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schematic

simulate this circuit – Schematic created using CircuitLab

Is this what you had in mind? External switch low and LED on at the same time with common gnd.

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  • \$\begingroup\$ Hi Tony. Yes this is what I meant, but this doesn't use the PNP. I know the circuit I put up doesn't need it, so I think I dug myself a hole trying to not have to draw out everything. I might delete this thread and make a different one wiht all the components and everything> I'm just very new to this schematic drawing and its very confusing for me. \$\endgroup\$ – user193513 Jul 13 '18 at 20:03
  • \$\begingroup\$ This is all you need \$\endgroup\$ – Tony Stewart EE75 Jul 14 '18 at 2:17
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Circuit to swith the high side of D2 and the low side of D1 from a single button press.

schematic

simulate this circuit – Schematic created using CircuitLab

the B-E junction of a bipolar transistor is like a diode and you need something to limit the current else the transistor will be damaged. here R1 limit the current Q1 and R4 limits the current to Q2

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