We were given this question in our intro to EE course:
Find the Thevenin equivalent network between points a and b for the circuit shown in the image below:
For the short-circuit current, I redrew the circuit as follows:
I'm a little confused about where to proceed from here, though. My prof said a cap across 0V potential has zero resistance and should be treated as a short-circuit. However, this creates a wire loop surrounding the dependent current source. I wonder if, since 0V = the potential across the cap, if the cap should be treated as an open circuit instead (since the cap's voltage is at the potential on either side of it, and this would remove the wire loop)?
Any ideas on how to proceed? Is there a mistake?
Bonus question: what would be the best way to approach finding the Open circuit voltage (Vx, in this case)? I've tried but get an ugly 3x3 complex matrix to solve.