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Given this circuit:

vs is small signal voltage.

enter image description here

I calculated the Operation Point and got that Vout must be equal to 0. Now let us say I want to put a capacitor in series with R2.

Does this change my operation point?

I still get that Vout must be equal to 0.

The upper and lower Voltages of the Amplifier are 5 and -5.

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  • \$\begingroup\$ What value VS voltage source has? \$\endgroup\$ – G36 Aug 3 '18 at 17:32
  • \$\begingroup\$ @G36 I edited the question. VS is a small signal voltage source so it won't affect my operation point. Take it as a 0. \$\endgroup\$ – Sijaan Hallak Aug 3 '18 at 17:35
  • \$\begingroup\$ Well if Vs is 0V (replace it with a short circuit) then yes Vo = 0V and adding a capacitor in series with R2 doesn't change it. \$\endgroup\$ – G36 Aug 3 '18 at 17:41
  • \$\begingroup\$ @G36 Even though my amplifier's lower and upper voltages are -5 and 5 volts? \$\endgroup\$ – Sijaan Hallak Aug 3 '18 at 17:43
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    \$\begingroup\$ Yep, supply voltage doesn't matter here in this case. \$\endgroup\$ – G36 Aug 3 '18 at 17:45
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Your bias point will be ground, as determined by R4. Whether R2 is cap coupled or not won't affect the bias point, but it will give you a low pass pole and a zero.

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