Logic: Output a 1 when a = 1 and b = 0

Question

I'm a hobbyist just discovering logic gates and would like to know, is there a logic gate that will only output a 1 when a is a 1 and b is a 0?

Truth Table

a | b | y
---------
0 | 0 | 0
0 | 1 | 0
1 | 0 | 1
1 | 1 | 0

Here is a schematic I made, that I think should work in theory, but would like it in one package.

Are chips like this readily available or is everything made up of individual gates?

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OFF TOPIC EDIT: IMGUR is currently not working with SE for me or for people in the comments so the way I got around that was to go imgur.com and uploaded the picture manually. Then right click the picture > Copy image address and then paste it here like so:

![logic](https://i.imgur.com/4OqbUN4l.png)

Answer 1

I'm pretty sure half a 7402 is all you need: use one gate to invert A and the other to NOR it with B:

^{simulate this circuit – Schematic created using CircuitLab}

 A   A'  B  |  Y
------------+----
 0   1   0  |  0
 0   1   1  |  0
 1   0   0  |  1
 1   0   1  |  0

Answer 2

This can be implemented with an AND gate with one inverted input, or with a NOR gate with one inverted input.

Devices that implement this logic are the (SN)74xx1G58, (SN)74xx1G97, and (SN)74xx1G98.

Answer 3

You could simply use a buffer chip with an active low enable.

Something like an SN74LV1T125 might work.

Hook A to A, B to OE, Y is your output.

Since the output tri-states, you will need a resistor to ground on the output.

Answer 4

You could implement the logic with a single 7437 logic chip using only 3 of the 4 gates in the package.

Answer 5

There are many chips which have both enable Hi and Lo for other features like One-Shots but not specifically this.

You can also use INV + NOR gate and swap inputs.

Answer 6

If all you want is to get the function in one package, you can do it with a multiplexer: half of a 74x153, for example. Connect A and B to the address pins and make all but one of the inputs low, while the AB' pin is high.