I am trying to power a number of different color LEDs with a 5V wall-wart power supply able to deliver 2 Amps.
I tried to make them light with equal intensity and I like them to be bright. (They get quite irritating to the eyes)
I get the following resistances:
blue: 5K, yellow: 350Ω, red: 150Ω, orange: 1K, green: 50Ω
Do the values make sense? The 150Ω and the 50Ω resistances get quite hot.
Am I doing anything wrong?
This diagram may help.
Figure 1. Figuring out the required voltage drop across the current-limiting resistor for a green LED at 20 mA. Source: LEDnique.
The graph shows the VF (forward voltage) of various LEDs at currents between 0 and 50 mA. We can see that at 20 mA the green LED will drop about 2.25 V. You are feeding from a 5 V supply so that means that the voltage drop across R is 5 - 2.25 = 2.75 V.
From Ohm's law we get \$ R = \frac {V}{I} = \frac {2.75}{0.02} = 137 \ \Omega \$. Pick the nearest standard value.
You can easily work out the resistor values for each of the other colours too.
For other currents slide the diode and resistor vertically to the desired value.
An alternate approach using the same graph is to draw the load-lines for a range of resistors.
Figure 2. Various 5 V resistor load-lines overlaid on IV curves.
[OP used] (1) blue: 5 kΩ, (2) yellow: 350 Ω, (3) red: 150 Ω, (4) orange: 1 kΩ, (5) green: 50 Ω.
Let's plot these points on the load lines.
Figure 3. The OP's resistor values found to give reasonably even brightness on a range of colours.
The plots indicate to me that there is a very large discrepancy in the efficiency (or possibly the optical focus) of the LEDs. If they were all the same efficiency the points should be close to the same height off the horizontal axis. From the results it appears that the blue is super-high efficiency but the green (which is in the most sensitive region of human vision) is terrible.
Probably. The green should have around 2-3V across it depending on the type. So if I use 2.5V then the current would be 50mA, which is too much to be safe for a 3mm LED. Also fits with the "get quite hot" for the resistor.
For long life you probably shouldn't run the LEDs over about 10-15mA. You can measure the voltage across the resistor and figure the current, closely enough.
I = Vres/R , where Vres is the voltage measured across the resistor terminals. The LED will take up essentially all the difference from the supply voltage.
If that's not satisfactory you have a couple of options- make them all dimmer, or purchase more efficient LEDs to replace the dim orange and green. I can tell you that modern high efficiency LEDs are almost painfully bright at 10mA, in those particular colors.
First, yes it makes sense that the smaller resistors are getting hot. Do the math using Ohm's law and you'll see that, for example, the 50 ohm resistor is dissipating about 0.4 watts.
Now to the rather wide range of values you've chosen, which I think is your main question, you are witnessing not only the different efficiencies of the different color LEDs, but the spectral sensitivity of your eye. So I would expect the values to be quite different based on color.
