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I am trying to solve this homework question:

enter image description here

I got the short circuit in the middle by removing a voltage source. The problem is to find the current flowing through R6.

What I tried:

  • Applying Star-Delta transformation on R3, R4 and R5 however it did not lead me anywhere.
  • I also cannot seem to be able to apply mesh analysis as no voltages are supplied to me.
  • I cannot convert the current source to a voltage source as there is no resistance in parallel with it.

Can someone please give me a hint as to how I should reduce this circuit?

Edit: Circuit after removing the short-circuited element R2:

Thanks to @Transistor and @MCG: I now was able to apply star-delta

enter image description here

Thanks to @Transistor and @MCG: I now was able to apply star-delta transformation which reduced the circuit to this:

enter image description here

I was able to solve this using current division.

P.S. The answer supplied by LTspice is 6 A for R6.

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  • \$\begingroup\$ Hint #1: One component is short-circuited so it can be removed. Redraw and post the modified circuit at the end of your question. \$\endgroup\$ – Transistor Aug 15 '18 at 9:06
  • \$\begingroup\$ @Transistor Hi! I tried doing that, but the simulation answer changed from 6A to 5A in both LTspice and CircuitLabs, so I thought that was an incorrect operation. Is it actually valid? \$\endgroup\$ – Rishav Aug 15 '18 at 9:08
  • \$\begingroup\$ You tried doing what? What component did you remove? \$\endgroup\$ – Transistor Aug 15 '18 at 9:09
  • \$\begingroup\$ I'm sorry, you meant removing the 15ohm resistor. I misunderstood. \$\endgroup\$ – Rishav Aug 15 '18 at 9:10
  • \$\begingroup\$ There are four 15 Ω resistors. Use the component numbers to be clear. \$\endgroup\$ – Transistor Aug 15 '18 at 9:11
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You've worked it out on your own. Congratulations. Here's how I would have approached it.

schematic

simulate this circuit – Schematic created using CircuitLab

Figure 1. The original. Note that R2 is short-circuited. It can be removed.

schematic

simulate this circuit

Figure 2. Note that R3 and R4 are in parallel.

schematic

simulate this circuit

Figure 3. Now we can add the series resistances.

schematic

simulate this circuit

Figure 4. This is as far as we need to go.

You can apply your current division here.

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