I'm currently evaluating the Semtech TS30042 step-down converter. My input voltage is 24V, output voltage is 5V. I followed datasheet recommendation in my layout in most aspects. The problem is, as soon as I short circuit the 2 clamp input ports (see second image below) the converter gets destroyed instantly! It seems there is some internal short circuit after that in the TS30042 because the voltage of my power supply drops to some mV and the current is on maximum. Short circuiting the 2 clamp ports, causes a short arc (as expected!).

My first self etched prototype board is this:

Prototype Board TS30042

After testing everything I ordered a professional board. Both with full ground plane btw.

Semtech TS30042

The only difference between these two is a slightly different layout and some different components. Especially the diode changed, previous was PMEG40T20ERX (now NRVTSA4100T3G), and the inductor was some Würth type, new one is 1267AY-4R7N=P3. Output capacitancy is 2x22µF (previously was 2x22µF+10µF). I replaced several components several times to be sure that it was not caused by a failed component.


I tried the same thing on my prototype board, but as often as I short circuited the input the same never happened. 4 converters are already destroyed. What could be the reason for that failure on my board and why doesn't it happen on my prototype board? Did I made any layout or circuit mistake?

FYI: The other 2 PAM2316 converters are not connected

Edit: Inserting a Schottky Diode from Vout to Vin as suggested also doesn't solve the problem.

  • 1
    \$\begingroup\$ I’m going to go ahead and give you a +1 for your probing technique and home etching. \$\endgroup\$
    – winny
    Aug 18, 2018 at 19:54

2 Answers 2


A lot of voltage regulators (switching or linear) do not like a fast discharge of voltage at the input and require extra protection to prevent the output capacitor discharging back through the circuit and causing "mayhem".

Maybe your prototype board had enough "variance" to hold-up the input voltage for long enough to prevent this problem arising or maybe the prototype chip was a little better than the ones you used for production.

Try putting a fast diode from Vout to Vin so that when the input voltage gets shorted it also discharges the output voltage virtually simultaneously.

  • 1
    \$\begingroup\$ The idea with the diode sounds plausible. However it doesn't solve the problem. At least it took 3 times short circuit to get destroyed (contingency?). I put the same Schottky Diode as used for D1. I didn't test another Diode yet since burning another 1.5$ for the regulator is a bit much, at least if the chance is high that it also gets destroyed. \$\endgroup\$
    – bkausbk
    Aug 18, 2018 at 20:53
  • \$\begingroup\$ Do you think there may have been an improvement with the diode? If so you might be also able to get away with a small series resistor (a few ohms) in the power lead shunted by a similar inductor to what you use on the output. I'm not suggesting this is a fix but something to try to prove the problem. \$\endgroup\$
    – Andy aka
    Aug 19, 2018 at 9:53
  • \$\begingroup\$ I don't know if there was an improvement. Yes it took 3 tries until the IC failed, but that may have been a coincidence. Such behavior was not mentioned anywhere in the datasheet. Because of this I doubt that this should happen with the example circuit provided in the datasheet. So this is either a layout failure of mine (I think so) or there is a problem with the batch of regulators I ordered. May be I'll try what you had suggested, but in the end I can't build the final circuit with that much component to fix potential IC issues because of the costs, better to use another IC then. \$\endgroup\$
    – bkausbk
    Aug 19, 2018 at 11:50

The fast low drop diode should have fixed things but it did not .If you are far enough down the design path and therefore feel that you must persist with the chip then try a diode in series with the input .This series will waste some voltage but it will stop the chip blowing up .


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