Simple question: how to find the frequency of oscillation of this circuit?
My attempt at answering the question is the following:
Suppose we are observing the circuit at when the voltage on the capacitor is zero. Q1 is ON and Veb is equal to 0.8 roughly. Applying KVL and neglecting base current through R2 (assume voltage at R2 equal to 10/11*9=8.18V) we get that voltage drop on R5 should be 0.02 V which implies an emitter current of Q1 of about 1.81 micro ampere. Assuming the collector current is roughly equal to the emitter current we can see that the capacitor needs 0.295 seconds to get to a voltage 4.5+0.8V which is going to turn on Q2 and Q3 for discharge. But that time gives me a frequency of about 3.43 Hz which is 1 order of magnitude off of what I read on the oscilloscope (45 Hz). Why is this so?
EDIT: Vcc is 9V