I am having trouble obtaining the power dissipation of IGBTs. It does not have a buit in diode and it isn't driving an inductive load. So I read in an application note that IGBT power losses are actually the sum of 2 kinds of power losses - 1. Static power loss 2. Switching loss
I figured this is the proper way to obtain overall power losses:
For my particular IGBT
- Desired Switch Frequency = 2Hz
- Duty Cycle = 2%
- Vce(sat) = 2.10
- Ic =130A
- Eon = 2.25mJ
- Eoff = 0.95mJ
- Ets = 3.20mJ
Static power loss = Vce(sat) * Ic * duty cycle
2.1 * 130 * 0.02 = 5.46w
Switching loss = Ets * Switching Freq
3.2e-3 * 2 = 0.0064w
lastly overall power dissipation is = Static power loss + Switching Loss
5.46 + 0.0064 = 5.4664w
please let me know if this is correcct or please show the correct derivation.
As noted by a member the correct values must be referenced in the Eon/off curves.
The Vce(sat) is also probably varied a bit but insubstantially so it will be kept identical to the previous derivation.
The correct values for Id=130a are: Eoff = 3mJ Eon = 7mJ Ets= 10mJ
Static Power Loss = 2.1 * 130 * 0.02 = 5.46w
Switching Loss = 10e-3 * 2 = 0.02w
The proper overall power dissipation turns out to be 5.46 + 0.02 = 5.48
the difference is ~2mW and it seems to make a bigger difference for higher frequency switching operation.