# Driving an RL circuit with an audio power amplifier

I'm using a Cerwin-Vega CV-2800 audio amplifier to drive the RL circuit depicted in the diagram below: simulate this circuit – Schematic created using CircuitLab

The amplifier is rated for 1400 W at 2 ohms, 900 W at 4 ohms, and 600 W at 8 ohms. I have two resistors with value 1 ohm and 68 ohms, both rated at 100 W. R1 takes on one of these values. The resistance of the inductor is 40 ohms, and its reactance at 50 Hz is $2\pi(50)(0.2) =$ 62 ohms. When R1 is 68 ohms, I see a 3.25 V drop across the resistor; however, when R1 is 1 ohm, I see only a 0.04 V drop.

Questions:

1. Is this change in voltage because the series circuit divides the voltage across the resistor and the inductor, and the inductor has a much higher impedance than the resistor and therefore drops most of the voltage supplied by the audio amplifier?
2. Why does the power rating of the amplifier go down as the impedance of the load goes up?
3. If I wanted to generate a current between 7-10 A amplitude through the RL circuit, is this something my amplifier is capable of? If not, how much power would I need, and is there even such an amplifier out there?