I've accidentally supplied the gate of an high power phase control thyristor (Vdrm=5200V and It(rms)=6500A) with a negative current (about two times the trigger current and four times the trigger voltage; ~900mA 12V DC) for a couple of seconds, a few times(4-5). The device apparently works fine when turned on by a positive gate pulse. Is it still safe to operate or it sustained internal damage being prone to failure?

  • 2
    \$\begingroup\$ What is the datasheet absolute maximum negative gate voltage? And other gate-related numbers? \$\endgroup\$ – Spehro Pefhany Aug 30 '18 at 1:33
  • \$\begingroup\$ Hello Spehro. Peak forward gate voltage =12V. Peak fwd gate current=10A. Peak reverse gate voltage=10V. Gate trigger voltage=2.6V. Gate trigger current=400mA. \$\endgroup\$ – Maris Aug 30 '18 at 1:40
  • \$\begingroup\$ Do you know it actually conducted 900mA or is that a worst-case scenario? \$\endgroup\$ – Spehro Pefhany Aug 30 '18 at 2:17
  • \$\begingroup\$ It is a measured value. \$\endgroup\$ – Maris Aug 30 '18 at 14:32

You are in a very rarefied environment with such a massive power semiconductor.

It's certainly possible that something has been degraded as a result of exceeding the abs max ratings and it won't show up until you subject the SCR to something approaching full load, perhaps in hot spots leading to destruction or something like that.

I would guess (and maybe you don't know) that if the trigger current or turn-on time has changed as a result of this "event" the chances are much higher, but that's a guess and worth approximately what you paid for it. It may be safer to avoid using it where failure would be inconvenient or dangerous.

|improve this answer|||||

A thyristor is a semiconductor device, so relies on fairly precise dimensions and material doping qualities. Failure modes are numerous, from cracks to impurity precipitation. See this Panasonic reference for more details on semiconductor failure modes.

Thus, if the datasheet's absolute maximum values have been exceeded then damage is possible and may be difficult to detect. The issue with exceeding the negative gate maximum voltage is that diode junction breakdown occurs allowing excessive current to flow in the device. 900mA @ 12V is more than 10W of power dissipated in a junction operating in a unspecified state. If it was for a few microseconds I'd be less concerned, but for a couple of seconds I would consider the part suspect.

I would expect the part has suffered some damage that may lead to early failure or behaviour of out specification.

Sorry to be the bearer of bad news.

|improve this answer|||||
  • \$\begingroup\$ A very interesting read, i will certainly look further into it, thank you and no worries. I'm not an expert by far, but I'm aware (afraid) of the immediate problem, that would be the reverse blocking capability, as this is a vital characteristic in our case (pulsed DC inductive circuit). I presume it could have been affected. \$\endgroup\$ – Maris Aug 30 '18 at 14:30

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.