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I have a two part question:

  1. What size battery storage is needed to provide 10A at 115v (I meant 115v AC) for 5 continuous hours?
  2. what size solar array (assuming proper alignment, etc.) would be required to charge the battery bank each day during the summer months?
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  • \$\begingroup\$ You need a 115V battery with 50 Amp-hours of capacity, and your solar panels should provide an average of 1150 Watt for 5 hours each day to break even. \$\endgroup\$ – vicatcu Aug 30 '18 at 23:37
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    \$\begingroup\$ Did you assume AC or DC? or consider cloudy days excess storage? \$\endgroup\$ – Sunnyskyguy EE75 Aug 30 '18 at 23:42
  • \$\begingroup\$ Hi Terry H, please check out this answer I wrote for a similar question. \$\endgroup\$ – bitsmack Aug 31 '18 at 0:25
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  1. From basic physics, (10 A)(115 V)(5 h) = 5750 Watt-hours. That's what the system has to cough up. The battery would have to store a bit more than that due to the converter from battery to 115 V AC having some loss.
  2. There are many variables here, not the least of which are what daily insolation you expect the system to be able to recharge a empty battery with. For example, let's say you decide to require 3 hours of full sun. (5750 Wh)/(3 h) = 1.9 kW. Let's say that together the converter from solar panel to battery, and the efficiency of the battery, and the efficiency of the inverter is 50%. That means you need about 4 kW capability in full sun.

The answer to both these questions really comes down to "Do the math!".

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