Simple problem that I can't solve.
On this AC circuit, find the current read by ammeter \$ A_3 \$ (the one in series with the resistor) given that \$A_1\$ reads 4A and \$A_2\$ reads 3A, assuming every current is read by its RMS value.
There are no given values for resistor and capacitor, but the textbook answer gives that \$A_1\$ reads 2.65A Here's what I've tried :
Since we're in AC, I figured voltage lags in the capacitor, so current must lead by 90 degrees. I tried using Kirchhoff's law with phasors in mind to find \$I_3 = I_1 - I_2\$ which would give \$4e^{j0} - 3e^{j\frac\pi2} = 4 - 3j\$.
However, the magnitude of this phasor is \$5\$, which is greater than the magnitude of \$I_1\$, which is impossible, since there are no current source in branch 2.
What am I missing? Thank you