-3
\$\begingroup\$

So a ac filter doesnt allow the dc component to pass through it, so the dc component would take a altetnative path where as the ac component would easily pass through it. My question is, where is dc component in the input wave?

\$\endgroup\$
  • \$\begingroup\$ It depends on what kind of signal. Every kind of signal can be represented by a sum of sine, cosine and a DC component. \$\endgroup\$ – Long Pham Sep 11 '18 at 14:26
  • 1
    \$\begingroup\$ I'm not sure I understand the question, but if the filter blocks DC, then it doesn't "go" anywhere. It simply appears across whatever component inside the filter that's doing the blocking, such as a capacitor. \$\endgroup\$ – Dave Tweed Sep 11 '18 at 14:49
  • 1
    \$\begingroup\$ @LongPham, to be more precise, every periodic signal can be decomposed into a sum of sinusoids and a DC component. Finite, non-periodic signals can be approximately understood by pretending that they were snipped from an infinitely long periodic signal. \$\endgroup\$ – user197845 Sep 11 '18 at 14:57
  • 2
    \$\begingroup\$ @besmirched: To be even more precise, nonperiodic signals can be represented with sines and cosines if you allow an infinite number of them. The Fourier Transform does not require periodicity. \$\endgroup\$ – Dave Tweed Sep 11 '18 at 15:04
  • \$\begingroup\$ @DaveTweed I dont know anything about fourier series etc... It will probably start next semester... So you are saying the input sine wave can be expressed as a sum of trig terms, and as we approach infinity the graph of the terms become flatter and flatter? ie a dc component? \$\endgroup\$ – Manav Shetty Sep 11 '18 at 17:31
2
\$\begingroup\$

DC component is the average amplitude over a cycle time period of the signal. So, basically in simple terms you can call the DC component as the bias given to an oscillating signal. For a sinusoidal signal with no bias it would be 0.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.