# Help Simplifying Boolean Expression

I'm currently stuck on the expression listed below. I applied almost all the Boolean algebra rules trying to figure it out, but no luck

Here is the expression:

AB'C*(BD+CDE)+AC'
Applying Distributive law:
AB'CBD + AB'CCDE + AC'
Applying A*A'=0 and C*C=C
AB'CDE+AC'
Factoring:
A*(B'CDE+C')
This is where I'm stuck. This is where I tried most of the rules and got nowhere


The books solution however is:

A*(C'+B'DE)


Then, I found this site and it also gave me a different solution. I don't know if the book has a wrong solution, or an alternate one

Boolean Algebra - Digital Electronics

Their solution was:

A * C'


Any suggestions? Thanks.

• Your book's answer is right. The web site you linked doesn't like "E". (Just look at the table they generate -- it is missing a column for E.) So just replace "E" with "F" on that web site and see what answer it gives you then. Note that it generates a proper table, too, if you use F instead of E. – jonk Sep 20 '18 at 4:30