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I may have posed this question before, but it bares repeating. Today I put a scope on the USB output of one of those universal travel power converters. I was appalled. It was noisy as all get out. I put my horizontal cursors on to measure the envelope of the spike infested waveform, and measured something like 4.3 - 5.8 Volts.

What I'm thinking about doing is putting that through a boost converter, and then through a linear 5V regulator to try and clean it up. Any better ideas out there?

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    \$\begingroup\$ Surely you've considered passive filtering...? That's kind of the go-to for noise in most applications that I know of. Boost to LDO will be a bit wasteful of money, space, and time due to extra components and complexity. \$\endgroup\$
    – Bort
    Commented Sep 26, 2018 at 21:39
  • \$\begingroup\$ @Bort feel free to propose an answer with a schematic... and don't call me Shirley \$\endgroup\$
    – vicatcu
    Commented Sep 26, 2018 at 21:49
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    \$\begingroup\$ Why are you surprised with quality of charging adapters? They are designed cheap, just to charge batteries (which are essentially strong "integrators"), and not to power any sensitive analog equipment... \$\endgroup\$ Commented Sep 26, 2018 at 21:58
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    \$\begingroup\$ This is typical load regulation for USB chargers. Even the chargers from better brands don't have stellar regulation. \$\endgroup\$
    – K H
    Commented Sep 27, 2018 at 0:50
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    \$\begingroup\$ Does it get better if you add some load? Unloaded switching power supplies often start oscillating heavily, as the frequency of the pulses generated to charge the output capacitor is low enough to pass the output LC filter. If you add a 500mA load, that should be a lot better. \$\endgroup\$ Commented Sep 30, 2018 at 14:55

2 Answers 2

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It seems more to be a ripple voltage/current you are talking about.

Linear regulator are not good at filtering ripple and are not device made for that.

A good and cheap way to improve ripple is to use what is called a capacitance multiplier circuit.

cap multiplier

Those circuit are very good at reducing ripple without to have to add massive capacitor and have a cheap cost.

To increase effectiveness, you can add several transistor or use darlington transistor as the value of the capacitor will be (virtually) increased by the transistor gain.

A Nice youtube video explains it here.


EDIT

There is also off-the-shelve components that implements this principle, such as the AP1158.

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    \$\begingroup\$ Nice suggestion. For the record but, linear regulators are amazing at filtering ripple. See the answer here for an example: electronics.stackexchange.com/questions/18111/… \$\endgroup\$
    – DSWG
    Commented Sep 27, 2018 at 0:19
  • \$\begingroup\$ You can watch the video I posted, it is explained why linear regulator are not good at it (at at 3:15) and even with demonstration. And also confirmed by my own experience. @DSWG \$\endgroup\$
    – Damien
    Commented Sep 27, 2018 at 0:23
  • \$\begingroup\$ Interesting, I've never encountered this circuit, I'll look into it, thanks. \$\endgroup\$
    – vicatcu
    Commented Sep 27, 2018 at 2:51
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    \$\begingroup\$ @vicatcu you can take a look at the AP1158 \$\endgroup\$
    – Damien
    Commented Sep 28, 2018 at 10:55
  • \$\begingroup\$ Seems to me that you would have a voltage drop across the transistor. \$\endgroup\$
    – JRE
    Commented Sep 28, 2018 at 11:26
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On some applications I've had luck following the recommendations of figure 2.5 in FT 000292. That being said, on sensitive circuits with high bit ADCs, that doesn't seem enough to kick the noise from some especially noisy sources. (For example, I've noticed an iMac provided very dirty power compared to a Lenovo.) In that case a boost/linear may be the only real option.

enter image description here

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