600 ohm modem transformer impedance calculation by formula

Question

From the datasheet of a modem transformer we have:

• Impedance, Primary: 600 Ω Typ. @ 1 kHz 1 Vrms*
• Shunt Inductance Lp, Primary: 3.2 H min. @ 1 kHz
• D.C. resistance @20°C: Primary = 82 Ω ± 15%

Also the impedance formula:

$$ Z= \sqrt{R^2+(XL-XC)^2} $$

How does 600 Ω result from 3.2 H and 82 Ω? (The X_C is negligible.)

Answer 1

How does 600 Ω result from 3.2 H and 82 Ω? (The XC is negligible.)

Think about what the spec says and read this below.