I have problem with an lm386 op amp in an non-inverting configuration. For the resistors, I take two equal resistors so i set a gain of 2. When i put a signal of 3.3 volts on the non-inverting pin, i should get 6.6 volts on the output on the op amp, but i get totaly different measuring. I have also measured the voltage on the inverting and non-inverting pins and i do not get the same voltage but i should. Also when no voltage is connected on the non-inverting pin (when its grounded) i am not getting 0 volts on the output, but i am getting zero point something volts. I have also tried to change the ic or the resistors but it didnt worked. So now i wanted to ask am i makeing a mistake or the mistake is in the ic. Every answer is welcome. Thanks a lot.
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2\$\begingroup\$ Welcome to EE.SE! Please post a schematic. \$\endgroup\$ – winny Oct 2 '18 at 19:37
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1\$\begingroup\$ 1. What op-amp are you using? Is it rail-to-rail on both input and output? 2. What are the power supply connections? \$\endgroup\$ – The Photon Oct 2 '18 at 19:50
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4\$\begingroup\$ Also, does your "LM386" tag actually relate to your question? LM386 is not an op-amp. \$\endgroup\$ – The Photon Oct 2 '18 at 19:52
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1\$\begingroup\$ An LM386 is not an opamp. You can't wire it up like one and expect it to work properly. \$\endgroup\$ – brhans Oct 2 '18 at 22:47
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Whenever you see a big difference between inverting and non-inverting terminals, one of three things may be happening:
- the open-loop gain is degenerate, so the error voltage cannot be reduced further
- the output is saturated, limited by the supply rails
- the measurement equipment was affecting the circuit
LM386 is an audio amplifier, not an op amp, even though it has some superficial similarity.
According to LM386 datasheet, the open-loop gain Av is only 26dB i.e. 20V/V. This is far from the ideal opamp where Av is considered near infinite.
Consequence of this reduced open-loop gain is that there will be significant difference between the inverting and non-inverting inputs, as you observed.
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\$\begingroup\$ You were nice not to say so, but the OP is miss-using the LM386 in terms of its intended function and design. It cannot be treated as an op-amp. Coupling capacitors mean it is intended for a single ended power supply. +1 \$\endgroup\$ – Sparky256 Oct 2 '18 at 23:40
