# Boosting 5V 2A wall wart [closed]

Is there a way to alter the 5V 2A wall wart into 5V 5A? I want to power neopixel LEDs but I just need slightly more current supply.

• Slightly? It's more than double. No, there is no way. Commented Oct 3, 2018 at 19:13
• No. "slightly more" isn't 2.5 times more. Commented Oct 3, 2018 at 19:13
– user105652
Commented Oct 3, 2018 at 21:06

Converting voltages and currents requires the total maximum power to not increase. In other words, input V * I >= output V * I (this is the concept of conservation of power). Therefore, it would be impossible to convert a 5V * 2A = 10W input to a 5V * 5A = 25W output because the 10W input is not greater than the 25W output.

• I would say input V * I >= output V * I. Given that nothing is 100% efficient, maybe just input V * I > output V * I Commented Oct 3, 2018 at 19:18
• yes, good point, updated answer
– mith
Commented Oct 3, 2018 at 19:18
• I guess the question is a bit different and can be rephrased as "is it possible to squeeze more power from a PS than it is rated for?" Commented Oct 3, 2018 at 19:19
• The question is about altering a wall wart to produce more power, not how to convert its output. However, your point is still valid and a good one, especially considering the OP might come back and ask about converting the output once he realizes that modifying the wall wart isn't going to work. Commented Oct 3, 2018 at 20:25
Is there a way to alter the 5V 2A wall wart into 5V 5A?

No. Not gonna happen. Fahgeddaboudit.

I just need slightly more current

A factor of 2.5 is a lot more than "slightly" higher.

If the 2 A wall wart could produce 5 A, then it would be sold as such and therefore fetch a higher price. The manufacturer had to pick something as the spec, and they picked 2 A.

These things are manufactured in high volume, so saving parts cost probably got significant design attention. Parts to support 5 A output would definitely cost more, and would take more space and weigh more too. You can't just tweak a resistor somewhere and have the device output 2.5 times more power.

If you want 5 V at 5 A, go buy a 5 V 5 A wall wart or power supply. These things are quite cheap nowadays. You can buy a ready-made unit for less than you can buy the parts for separately in low volumes.

What you are asking to do just doesn't make sense. Not even close.