This refers to the most common type of semiconductor heating cable I've installed, self regulating heat trace. A variety of temperatures are available but the bulk I have seen is used to prevent lines or devices from freezing.
You can see from the image that the cable is composed of two tinned copper bus wires of low resistance connected by a body of semiconductive plastic, and then a number of protective/insulation layers.
Different materials have different resistances per cross sectional area or resistivity, and a larger wire will have lower resistance given the same material. Power dissipation(\$P\$) is equal to current(\$I\$) squared times resistance(\$R\$) or voltage drop(\$E\$) times current, or in formulas:
by controlling where the resistance is, you control where the power is dissipated, and that control is the function that auto regulating semiconductor heater cables perform for you.
The semiconductor is chosen based on the desired regulation temperature to have high resistance at or above that temperature, and lower resistance the farther below that temperature it reaches. The advantage to this setup is that the cable is able to provide differential heat only where it is needed across its length. You can take an outdoor rooftop plumbing line that passes through multiple different ambient temperatures, run a single cable along the entire length of it and insulate it. Because the cable produces heat only where it's needed, you don't have to be concerned with doubling it up or overheating the portion that is in a warm environment. You can also keep the cable hooked up year round without active control of the circuit because during times when the temperature is high, the semiconductor resistance is high and very little power is dissipated. For critical building function, they use no more power than is necessary(in this use case) to keep the pipe from freezing, and thus they minimize the electrical load on a building UPS or backup generator.
The low resistance backbone cables dissipate very little power, and just get the current to the places where the semiconductor is cold enough to have lower resistance. They still have some power dissipation, especially when a cable is first turned on in a colder-than-setpoint environment and a current surge occurs, but they are sized so that their power dissipation will be insignificant compared to that of the semiconductor once it has reached normal operating temperature.
So at points along the length of the cable, temperature will drop below setpoint and at these points, the current flows from the low resistance bus cables across the comparably much higher resistance of the semiconductor and produces heat. The resistance of the semiconductor at the points where current flows is still much higher than the resistance of the copper, but low enough to allow current to flow.
The current increases proportionally to the decrease in resistance, but the power dissipated increases by the square of the current, so the device reacts aggressively to maintain its temperature. A 10% decrease in resistance will result in a 10% increase in current and a 10% squared increase in power dissipation. This means that the farther below its setpoint the cable is, the more quickly it will heat back up to its setpoint.
I've been looking for a graph that shows the semiconductor resistance "knee", but haven't found one yet, but hopefully this improves the answer for now.
Wires have little resistance and generate little heat.
Heater has much higher resistance and generates lots of heat.
With 10 Amp flowing heater would generate 1000W, wire 0.1 W each.