I've been wondering and testing selfmade magnets by wrapping iron with wires and applying a voltage to it which makes it a bit magnetic. I've been looking around the internet and can't seem to find formula's or calculation examples on this subject. If I have wires of example 0.22mm² and a voltage of 3.3V, 2Amps, 25 turns, how big must the iron core be to lift a weight of example 5 grams?
How much voltage and current do I have to apply when I have a constant value of the thickness of the copper wire, windings and iron core to lift 5gr.
Also, if I halve the amount of windings but double the thickness of the copperwire, is that the same?
Apologies in advance for possible duplicates of this matter, I've tried to use this http://onlinecalculators.brainmeasures.com/Electric/SolenoidCoil.aspx
When I fill in:
Current = 2A Area = 0.00439m2 = Cilinder with a diameter of 20mm and a length of 60mm Number of turns = 25 turns length of the gap = 0.001m = 1mm gap (I intent to touch the magnet if the intented object) Results = 0.069N = 7 grams.
However, the calculator doesn't seem to care about the coil thickness/wire diameter which I doubt the results of it capabilty of lifting that amount of weight.