I'm using TLV71333P-Q1 to regulate the input voltage of 5 V to get the output of 3.3 V.
It says in the datasheet that in normal operation, "The input voltage is greater than the nominal output voltage added to the dropout voltage" and when I looked up in the Electrical characteristics table there's a field of dropout voltage (VDO).
5V - 3.3V = 1.7 V is clearly greater than all of the above values but VDOs are different as the different of IOUT.
The question is how can I determine the IOUT of this regulator. And if my input voltage is lower than 5 V (may be 4 V or 4,5 V), how can I determine the VDO.