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I'm just a beginner, trying to understand an antennas and transistors as an amplifier, I'm studying, please correct me.

Here we have a voltage source, PNP bipolar transistor emitter-base-collector from left to right, speaker and an antenna (just a wire). All these stuff is connected as shown below. Red curves are electric components of EM waves.

enter image description here

As I understand the original signal (from the antenna) plays a role of a switcher in transistor, as a result we will have something like this:

enter image description here

So, will the scheme work?

My doubt why it will work or not:

  • This is not an antenna, hence the required "minus" on the base will be too low.
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    \$\begingroup\$ So, will the scheme work? NO if you want to learn how to work with transistors, look at how others use them. Trying to invent your own way how to use a transistor ends in failure and broken transistors. There are plenty of resources to be found showing you how a transistor can be used. Look at those and learn from that. \$\endgroup\$ – Bimpelrekkie Oct 14 '18 at 20:51
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    \$\begingroup\$ If you are very close to a very high power AM transmitter, then, yeah, you could hear something out of it. I used to work with a German guy who grew up in Berlin during the cold war. The US operated "Voice of America" radio station was located in West Berlin. It was so high power, that all you needed to receive it (if you lived in West Berlin) was a speaker and a diode. Ground one terminal of the speaker, hold one terminal of a diode in your hand, touch the other terminal to the free terminal if the speaker, and -presto - instant AM radio receiver. \$\endgroup\$ – JRE Oct 14 '18 at 20:54
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    \$\begingroup\$ Yeah, it is a bit different. Yours does use a N-P junction as a rectifier, though. And, AM radio doesn't operate at 80MHz. In the range you are talking about, commercial radio uses frequency modulation rather than amplitude modulation - this thing will never pick up an FM signal. And sure as heck won't do anything at 80MHz. \$\endgroup\$ – JRE Oct 14 '18 at 21:08
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    \$\begingroup\$ Commercial AM radio operates below 1.5MHz. \$\endgroup\$ – JRE Oct 14 '18 at 21:09
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    \$\begingroup\$ "Hear," yes. The base - emitter junction of a transistor is a diode. The simplest AM receiver is an antenna, a tuning circuit, a diode (as a demodulator) and a speaker. The battery doesn't really matter. But, when I said "high power and close by" I meant like "megawatt AM transmitter literally next door." \$\endgroup\$ – JRE Oct 14 '18 at 21:54
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You might actually hear something with that circuit arrangement, but a minor modification would likely improve reception considerably.
The problem with antenna connection:
The transistor complicates circuit problems. A simple diode AM radio detector illustrates why this circuit doesn't work well. You need an antenna, a ground connection, a rectifying device (diode), and an audio transducer (preferably headphones) to make a simple AM receiver.
The circuit at left has the same problem as your PNP detector. The diode sits between antenna and headphones, and generates uni-directional current from an AM-modulated carrier impinging on the antenna. But where does this current go? Any diode current charges up the antenna, which appears as a small capacitance to ground. The diode becomes reverse-biased, and very little audio current flows into the headphones.
The circuit at right produces audio current that flow through the headphone (in one direction). Current flows through the headphone in pulses, perhaps a million pulses-per-second. Those pulses vary from zero to some uni-polar amplitude that is proportional to modulation...that's audio that you can hear.no-worky(left),yes-worky(right)
Like the faulty diode detector at left, a junction of the PNP transistor does the diode's job of generating current from the AM-modulated signal provided by the antenna. And much of this current produces voltage at the antenna that reverise-biases the rectifying PNP junction, rather than producing audio current that flows through the headphone. You can use a PNP transistor just like a diode of the right-hand circuit above, but it will provide no signal amplification:

schematic

simulate this circuit – Schematic created using CircuitLab


Once you introduce a bias voltage for the transistor, amplification is possible. With the introduction of a tuned LC circuit, the transistor and LC circuit can be made to oscillate, which can be viewed as an infinite-gain amplifier.

A one-transistor regenerative receiver can amplify very feeble radio signals, if it is biased close to the point of oscillation. However, it is a more advanced project that has frustrated many eager builders, since the tuning and regeneration controls interact. Setting regeneration to its critical most-sensitive position is rather difficult.



EDIT

Long-wire antenna acting as a capacitor that is charged to a DC level is the problem to be solved. A bleed resistor could help two ways:

  • discharge antenna DC voltage

  • bias the transistor closer to conduction

Too small resistance adds so much collector-emitter current that you have a linear amplifier. The transistor's base-emitter junction must be biased by this resistor into its most non-linear region so that the 1 MHz audio-modulated antenna signal can generate audio collector current. A resistor value of a few MEGohms might be optimum.
Also, be aware that the earth connection is often neglected. Antenna radio frequency signals must have an earth reference point. This circuit is below, left.

You could use transistor gain two different ways:

  • Amplify linearly radio signals, then detect with a diode rectifier

  • Detect with a diode, then amplify audio.

Diode detector followed by a linear audio amplifier might be the easier approach: transistor gain at low (audio) frequencies is easier to achieve than gain at higher (radio) frequencies. Circuit below, right. These circuits are hobbled by including no tuned circuits. The inductor L1 would work better if it could be resonated with a capacitor (which is paralleled with antenna capacitance) at the radio frequency.
Be aware that the regenerative receiver produces superior results compared to these.

schematic

simulate this circuit

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  • \$\begingroup\$ My professor say, that the idea of transistor is, that you can control huge currents by tiny currents. Your schemes not about this idea at all. I built the scheme with this idea, and I had a doubt that it will not work because the wire(antenna) will charge(due to even a single wire has a capacitance)/ or current will be too low to open an emmiter-base pn transition. \$\endgroup\$ – Artur Oct 15 '18 at 8:46
  • \$\begingroup\$ @Artur added a few circuits that could amplify signals, but not by much. The regenerative receiver circuits do much better. \$\endgroup\$ – glen_geek Oct 15 '18 at 15:26
  • \$\begingroup\$ What is the purpose of the capacitor in the first scheme? \$\endgroup\$ – Artur Oct 15 '18 at 16:06
  • \$\begingroup\$ Its a rule I follow - any radio frequency circuits have a bypass capacitor added on the DC power supply input. The wires to a DC supply may be long, and add inductance. The capacitor is placed with short leads from transistor emitter down to the audio transducer (speaker), and resistor at ground. The capacitor value is chosen to have a low impedance at the radio frequency. \$\endgroup\$ – glen_geek Oct 15 '18 at 16:19
  • \$\begingroup\$ So the first scheme will work? \$\endgroup\$ – Artur Oct 15 '18 at 16:24
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A real radio circuit has some LC resonating circuits to select the radio frequency. Your circuit will no LC will pickup many radio stations at the same time if its transistor was biased correctly.

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  • \$\begingroup\$ I didn't say anything about radio at all \$\endgroup\$ – Artur Oct 15 '18 at 8:32
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    \$\begingroup\$ @Artus: "Radio" is the common word for all the things being discussed here. \$\endgroup\$ – JRE Oct 15 '18 at 15:51

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