How to design a voltage divider to optimize the measurement error?

Intuitively I would take the same ratio $$\frac{load}{divider} = \frac{divider}{measurement}$$ As follow: the voltage is roughly divided by 5. The divider induces 1% error on the load, and the measurement 1% error on the divider.

Is it a good practice?


simulate this circuit – Schematic created using CircuitLab

  • \$\begingroup\$ You can use a voltage follower. Adding a voltage follower to the voltage divider circuit isolates the load impedance (Rmeasurement) so that VOUT is dependent upon R1 and R2, not Rmeasurement. \$\endgroup\$ – Remco Vink Oct 16 '18 at 8:31
  • \$\begingroup\$ yeah sure, but I want to make it simple, I have 32 inputs in parallel and do not want to implement 32 voltage followers :) so I want to optimize my voltage divider \$\endgroup\$ – Rémi Baudoux Oct 16 '18 at 8:36
  • \$\begingroup\$ What makes you say that the "divider introduces 1% error on the load"? The voltage across the load and across the divider must be identical (for an ideal voltage source). \$\endgroup\$ – Elliot Alderson Oct 16 '18 at 13:27

This is about what I was looking for:


enter image description here

| improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.