I have an L298 H-Bridge, but I cannot, for the life of me, get it to work. I have connected Vss to +5v, GND to ground, Input 2 to +5v, Enable A to +5v, Input 1 to ground, Vs to +5v, Output 2 to a motor terminal, Output 1 to the other motor terminal, and Current Sensing A to ground. The motor will not spin. I lack a volt meter at present (very short term, I usually do have one), so I tried tasting the wires. There is no electrical tang whatsoever (power supply does taste tangy, so that's not the problem!) This is the simplest circuit I could think of to test this thing and it will not work. Please help me!
It is always an immensely good idea [tm] to provide a datasheet linklike this
What you describe SOUNDS OK.
Do you have protection diodes?
Without them it may have switched once and then shuffled off its mortal coil*.
(*=made magic smoke, visible or not).
You will never guess my problem. I will give you a hint: it wasn't my wiring... sort of...
The stupid package this chip is in doesn't fit very nicely in a breadboard. I had rocked the chip back wiring it up which disconnected all of the pins on one side. This is the second stupid-mistake question I have asked on stack exchange recently. What is the appropriate action from here?
I just had a similar problem with the L298 not working. It turned out that the sense pin must be connected to GND (via a current sense resistor or not) as it somehow controls the output current, and when not connected, the output current is quite close to 0.
This was not quite clear in the datasheet which, in the introduction, states that
the corresponding external terminal can be used for the connection of an external sensing resistor.
which sounds like one could optionally connect something to the sense pin if one then wanted to measure the current that flows. However it becomes clearer with this:
The current that flows through the load comes out from the bridge at the sense output : an external resistor (Rsa ; Rsb .) allows to detect the intensity of this current.
So the Sense terminals are actually the emitter of the respective stage.