I've been using the Atmel Power Debugger to sort out power consumption issues on some µController based circuits... and have been pretty pleased. Unfortunately, it's limited to a maximum of 5.5 volts and I need to work on some circuits which are a little above that range, up to 18 V.

Can someone recommend a method and or off the shelf hardware to help me get going on DC power measurements in the 0-18 V range?

What are some options for logging power consumption over several hours... maybe as long as 24 hours to evaluate circuit / firmware performance?

A different post (How to Measure Power Consumption on Extremely Low Power Devices?) mentioned the µCurrent Gold Multimeter adapter to utilize with a multimeter, but it's out of stock.

Any suggestions would be greatly appreciated!

  • \$\begingroup\$ Providing you don't want to measure sleep state current below about 100uA you could use a INA219 and Arduino to log power usage. \$\endgroup\$ – Jack Creasey Oct 23 '18 at 5:59
  • \$\begingroup\$ A few years ago I had a similar issue, and I plumped for the Uni-T UT71D - cheap (considering what it offers) and has data logging. EEVBlog also recommended it. \$\endgroup\$ – Greenonline Oct 23 '18 at 6:54
  • \$\begingroup\$ I do not know what current range you are in, but perhaps the VA mode on the EEVblog 121GW? \$\endgroup\$ – Jeroen3 Oct 23 '18 at 7:20
  • \$\begingroup\$ Labjack is a decent low-cost and easy-to-use data acquisition system. You would need to add a current sensor of some sort (like the INA169 breakout board). In addition, you would need a resistor divider for the voltage to bring it down within range of the labjack ADC input. You can place the divider so that the divider current does not flow through the shunt. Log all data to a PC. \$\endgroup\$ – mkeith Oct 23 '18 at 7:31
  • \$\begingroup\$ On any of these shunt-based current measurement devices (such as INA219 and INA169) you can increase the shunt resistor value to increase sensitivity. You only run into problems if the current varies over a wide range. Larger shunt means larger voltage drop. \$\endgroup\$ – mkeith Oct 23 '18 at 7:33

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.