I have been trying to solve this basic FPGA problem with multiplexers, but I cannot garner the meaning of the notation 0/1. Can someone throw some light in this regard? What do notations like 0/1 mean? Is it that the input can be either 0 or 1?

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2 Answers 2


You are correct in your understanding. The [0/1] represents a 1-bit ROM (or Lookup Table). Each of these 1-bit ROMs are programmed by a bit-stream when the device is turned on in order to configure the behaviour of the logic.

In this case all four 1-bit ROMs can be programmed to allow all possible outputs based on the two inputs to be configured.

For example if you set the value in the four ROMs to [0 0 0 1], you would form an AND gate. Set to [0 1 1 1] you form an OR gate. You can make any of the sixteen possible outputs.

In terms of solving the question, I presume you are given more information as to the value in the ROMs.

  • \$\begingroup\$ So, just as an addendum, for inputs like 0/1, we cannot have any definite output in this case, right? \$\endgroup\$
    – Curiosity
    Oct 28, 2018 at 12:58

Yes, the input can be either 0 or 1. This is a lookup table, the fundamental unit of FPGAs; when programming the FPGA you program in what each of these inputs is.

I don't think this question is solvable without more information. You would need to know what at least one of the programmed values is.

  • 1
    \$\begingroup\$ Or at least you need to name the ROMs, so you can answer something like "When A=1 and B=1, the output is whatever is in ROM number 3". \$\endgroup\$
    – The Photon
    Oct 28, 2018 at 15:44

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