Just wondering what's the wiring, kinda confused on how this actually looks on a schematic.
Does this look correct?
simulate this circuit – Schematic created using CircuitLab
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2\$\begingroup\$ You could always read the rest of the datasheet. \$\endgroup\$– user253751Oct 31, 2018 at 4:19
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\$\begingroup\$ I did, I never got onto anything \$\endgroup\$– LeocOct 31, 2018 at 4:27
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\$\begingroup\$ Perhaps if you know what the difference between a potentiometer and a rheostat is, it would help. \$\endgroup\$– TimWescottOct 31, 2018 at 4:53
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\$\begingroup\$ Oh interesting, so its just a single variable resistor? \$\endgroup\$– LeocOct 31, 2018 at 5:45
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2 Answers
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It's a (simulated) variable resistor between pins 5 and 6. From Wikipedia:
Of course there are some differences with real resistor, such as the requirement that both ends of the resistor must always remain within the power supply rails of the chip for proper operation. The "wiper resistance" is in series with the "element resistance" which means some nonlinearity that will vary with voltage of the simulated rheostat and the supply voltage.
answered Oct 31, 2018 at 10:24
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\$\begingroup\$ How would one use it in a feedback loop in an amplifier, to automate gain? \$\endgroup\$– LeocOct 31, 2018 at 17:39
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\$\begingroup\$ You could use it as the feedback resistor in an inverting amplifier, in conjunction with a fixed resistor R. Gain = -Rf/R. Or swap resistors so you get 1/gain proportional to Rf. Etc. But it will likely introduce some distortion. \$\endgroup\$ Oct 31, 2018 at 17:52
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\$\begingroup\$ Would it be too much to see a schematic on how its hooked up? I am confused on the wiper pin because I want to use an arduino to control the resistance values \$\endgroup\$– LeocOct 31, 2018 at 18:05
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\$\begingroup\$ This sounds like a new question- it will have to get int design of a single supply amplifier probably, so more than just this question scope. \$\endgroup\$ Oct 31, 2018 at 18:50
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