# Calculate the Norton Resistance and Current and the Thevenin Voltage of the following circuit

U=10 V, R=10 ohm

I calculated the resistance as such: 1/Rt = 1/R + 1/R <=> Rt = R/2 = 5 ohm

To calculate the voltage I did KVL as such: U - 2Ur = 0 <=> Ur = 5V, where Ur is the voltage in the resistors And then by applying KVL to the closed network that goes from a to b passing through the resistor, I got Ut=5V

Then I calculated the current using U=RI, and I got I=1A. Is this correct? Because in my solutions I=0,5A

You have done the correct method; found the open-circuit terminal voltage, which is the Thevenin voltage. You have then found the Thevenin resistance - also correct. You have then used the transform $$\ I_n = V_{th}/R_{th}\$$ to find the Norton current, correct again.