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I am using this driver IC, ZXGD3005E6TA. I am using a Pi as my controller, which has an output of 3.3V. The Vcc of my system is 12V.

I cannot determine if the IC will output the 12V when I supply 3.3V at the Vin pin or if it will only match the Vin and output 3.3V on the source pin - while still providing higher current.

How will this IC actually behave?

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    \$\begingroup\$ 0..Vcc -> Vin is just a signal \$\endgroup\$ – g_1_k Nov 7 '18 at 7:19
  • \$\begingroup\$ Thanks, if that is the case I was not able to find on the datasheet what the threshold voltage for Vin is. Will the 3.3V from the Pi be enough to trigger the source to 12V? \$\endgroup\$ – A.S. Nov 7 '18 at 7:41
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Nope. It wouldn't work as the driver needs Vcc-0,8 before it switches.

You can use the MCP1406/07 as it is much more versatile.

Remember when you're using a MOSFET driver, that you must place a decoupling capacitor between Vdd and GND (the MCP1407 has two Vdd pins) and a low ESR 0.1 uF electrolyt capacitor between Vdd and GND, to deliver the charge quickly.

On the input place a pulldown resistor.

:)

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  • \$\begingroup\$ I believe that info on the table indicates that when Vin = Vcc that the output voltage will typically be Vcc-0.8. Not that the triggering voltage is Vcc-0.8. Similarly that the output voltage when low will be at most Vee+0.5. I will look at that other driver and see if it may work better for my application. Thank you. \$\endgroup\$ – A.S. Nov 7 '18 at 8:13
  • \$\begingroup\$ The datasheet for the ZXGD3005E6TA is very hard to decode. I tried looking for a PSpice model without any luck. :) \$\endgroup\$ – Maarten Kjær Den Haan Nov 7 '18 at 8:36
  • \$\begingroup\$ I looked at MCP1407 and decided to use it for my design. The datasheet is much more detailed and clearly works with TTL level input. Thanks again. \$\endgroup\$ – A.S. Nov 7 '18 at 11:06

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