# What does floating source mean in this context?

What makes the load in the below circuit floating?:

Does that mean the load does not have a ground shared with the circuit ground?

• it doesn't look particularly floating to me.. I'd call that a high-side load, and the active circuit a current sink. it's not connected to circuit ground but the supply rail is still an AC ground – Jasen Nov 9 '18 at 0:03
• Normally, floating source means no connection to earth ground. Usually there is an isolating transformer between the power supply for the source and the mains. In that diagram, the top of the load is fixed at Vcc, so I would not call that floating. – Jack B Nov 9 '18 at 0:25
• It is only floating in the sense that VCC can change considerably without significantly changing the current in the load resistor. Note that I usually do these using MOSFETs as the pass transistor, because a BJT requires a small but not necessarily well-known base current to do the same thing -- with a MOSFET, you know the gate current is zero at DC. – TimWescott Nov 9 '18 at 0:53
• The quick answer is yes. Making a current source with a grounded load is typically more work, but it can be done. See Howland current source. – WhatRoughBeast Nov 9 '18 at 1:01

Then if so Ic=Ie. Ie = $$\VDC+Vsin/Rsense\$$. The value of RL does not count in terms of current flow as long as it is below the maximum value for Vsense loop to work. If RL is open or 'infinite' the feedback loop is broken and the op-amp output will be close to the Vcc rail.
RL 'floats' in the sense that it can have an extreme range of values yet Ic does not change. RL 'sees' only a voltage change across it as it changes values to keep the current constant if the value of RL changes. As it rises in value so does the Vdrop across RL, until it reaches Vcc-Vce-Vdrop of Rsense. That is as high as RL can go and have a stable circuit. If RL is shorted or very low ohms, nothing bad happens as the servo-loop keeps the current locked in based on Ie = $$\VDC+Vsin/Rsense\$$.