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In closed magnetic circuit, How many turns are when a conductor winded around a square mild steel core with permeability (Ur=2410)?

The outer length is 20 cm and inner length is 16 cm. The current measured is 1.482 A. Length of the coil is 10 cm

Any Hint where to begin? enter image description here

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    \$\begingroup\$ The number of turns determines the inductance L of the coil, which affects the current flowing through it. But I think there is missing some information. What is the voltage applied? \$\endgroup\$ – U.L. Nov 11 '18 at 19:43
  • \$\begingroup\$ The volt is not given. \$\endgroup\$ – Hussam Mj Nov 11 '18 at 19:54
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    \$\begingroup\$ I edited the question and assumed you mean you mean 1.482 A, not 1482 A (where 1,482 is the US way of writing). \$\endgroup\$ – Michel Keijzers Nov 11 '18 at 19:55
  • \$\begingroup\$ I did write 1,482 A \$\endgroup\$ – Hussam Mj Nov 11 '18 at 19:56
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    \$\begingroup\$ there isn't enough information to solve this... What guage wire. What inductance, what frequency AC, what voltage (Vs...) ... there is no depth so the window of the core is unknown. \$\endgroup\$ – JonRB Nov 11 '18 at 20:17

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